t^2-14t-22=0

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Solution for t^2-14t-22=0 equation:


Simplifying
t2 + -14t + -22 = 0

Reorder the terms:
-22 + -14t + t2 = 0

Solving
-22 + -14t + t2 = 0

Solving for variable 't'.

Begin completing the square.

Move the constant term to the right:

Add '22' to each side of the equation.
-22 + -14t + 22 + t2 = 0 + 22

Reorder the terms:
-22 + 22 + -14t + t2 = 0 + 22

Combine like terms: -22 + 22 = 0
0 + -14t + t2 = 0 + 22
-14t + t2 = 0 + 22

Combine like terms: 0 + 22 = 22
-14t + t2 = 22

The t term is -14t.  Take half its coefficient (-7).
Square it (49) and add it to both sides.

Add '49' to each side of the equation.
-14t + 49 + t2 = 22 + 49

Reorder the terms:
49 + -14t + t2 = 22 + 49

Combine like terms: 22 + 49 = 71
49 + -14t + t2 = 71

Factor a perfect square on the left side:
(t + -7)(t + -7) = 71

Calculate the square root of the right side: 8.426149773

Break this problem into two subproblems by setting 
(t + -7) equal to 8.426149773 and -8.426149773.

Subproblem 1

t + -7 = 8.426149773 Simplifying t + -7 = 8.426149773 Reorder the terms: -7 + t = 8.426149773 Solving -7 + t = 8.426149773 Solving for variable 't'. Move all terms containing t to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + t = 8.426149773 + 7 Combine like terms: -7 + 7 = 0 0 + t = 8.426149773 + 7 t = 8.426149773 + 7 Combine like terms: 8.426149773 + 7 = 15.426149773 t = 15.426149773 Simplifying t = 15.426149773

Subproblem 2

t + -7 = -8.426149773 Simplifying t + -7 = -8.426149773 Reorder the terms: -7 + t = -8.426149773 Solving -7 + t = -8.426149773 Solving for variable 't'. Move all terms containing t to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + t = -8.426149773 + 7 Combine like terms: -7 + 7 = 0 0 + t = -8.426149773 + 7 t = -8.426149773 + 7 Combine like terms: -8.426149773 + 7 = -1.426149773 t = -1.426149773 Simplifying t = -1.426149773

Solution

The solution to the problem is based on the solutions from the subproblems. t = {15.426149773, -1.426149773}

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